3x^2+3cosx-2sinx=2

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Solution for 3x^2+3cosx-2sinx=2 equation:


Simplifying
3x2 + 3cosx + -2sinx = 2

Reorder the terms:
3cosx + -2insx + 3x2 = 2

Solving
3cosx + -2insx + 3x2 = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2insx' to each side of the equation.
3cosx + -2insx + 2insx + 3x2 = 2 + 2insx

Combine like terms: -2insx + 2insx = 0
3cosx + 0 + 3x2 = 2 + 2insx
3cosx + 3x2 = 2 + 2insx

Add '-3x2' to each side of the equation.
3cosx + 3x2 + -3x2 = 2 + 2insx + -3x2

Combine like terms: 3x2 + -3x2 = 0
3cosx + 0 = 2 + 2insx + -3x2
3cosx = 2 + 2insx + -3x2

Divide each side by '3osx'.
c = 0.6666666667o-1s-1x-1 + 0.6666666667ino-1 + -1o-1s-1x

Simplifying
c = 0.6666666667o-1s-1x-1 + 0.6666666667ino-1 + -1o-1s-1x

Reorder the terms:
c = 0.6666666667ino-1 + 0.6666666667o-1s-1x-1 + -1o-1s-1x

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